1. Introduction
Let
be the complex variable with
and let
be the set of all the primes. The celebrated Riemann zeta-function
is defined by
for
, where both the Euler product and Dirichlet series are absolutely convergent, and hence analytic in that right half-plane. It is continued meromorphically over the whole complex plane with the unique simple pole at
with residue 1 by way of the functional equation and the meromorphic continuation in the critical strip
. It is known that
has infinitely many zeros in the critical strip, called non-trivial zeros, which are essentially connected with the distribution of primes. The famous Riemann hypothesis states that all of the non-trivial zeros lie on the critical line
, which gives the best bound for the error term for the prime number theorem. Since the introduction by Riemann, the function
has been the main impetus for the development of analytic number theory in the area of distribution of primes. The situation has been drastically changed by S. M. Voronin’s dicovery [
1] of universality of
, i.e., attention has been drawn to function-theoretic properties. By symmetry (functional equation), it is enough to consider the right half of the critical strip
. Then, the Voronin universality means that the zeta shifts
approximate all analytic non-vanishing functions defined in
D. The universality of
has been also discovered by A. A. Karatsuba and S. M. Voronin [
2], and developed by S. M. Gonek [
3], B. Bagchi [
4], J. Steuding [
5], K. Matsumoto [
6], J.-L. Mauclaire [
7], the first author [
8,
9], their students, and others. A wide survey of universality of zeta functions and its applications is given in [
10].
To state the modern version of the Voronin universality theorem, we introduce notation, which will be used throughout. Let
be a family of compact subsets of
with connected complements, and let
(with
) be the class of continuous functions on
K that are analytic in the interior of
K. Let
denote the subspace of
consisting of non-vanishing functions. Then, the modern version of the Voronin universality theorem says (see, for example, [
5,
8]) that for every
,
and
,
where
and
means the Lebesgue measure of a measurable set
. Furthermore, the lower limit may be replaced by a limit for all but at most countably many
. This proviso is valid in the Theorems 1–2 and 4–6, and it will be omitted.
The impact of (
1) was enhanced by B. Bagchi’s result [
11] that inequality (
1) with
is equivalent to the Riemann hypothesis that all non-trivial zeros of
(zeros in the strip
lie on the critical line
.
From (
1) arose an enormous number of new problems. The shifts
in (
1) can be replaced by more general shifts
with a certain function
. In [
12], the function
,
, was considered; in [
13], a more general differentiable function
was used. Using generalized shifts also allows one to investigate a simultaneous approximation of several analytic functions
, say, by
r-tuple of zeta-shifts
. For example, in [
14], the joint approximation by shifts
, where
are real algebraic numbers linearly independent over the field of rational numbers, was obtained. Moreover, inequality (
1) means that there are infinitely many shifts
approximating a given analytic function
with accuracy
. Although, such a theorem claims the existence of shifts approximating a given analytic function, it does not give any concrete approximating shift, which is inevitable due to the metrical nature of the assertion. As a rephrase, the effectivity of universality theorems is interpreted as the specification of the interval
containing
with approximating property. The first attempt to solve this problem was made by A. Good [
15]; R. Garunkštis applied and developed Good’s ideas for the effective approximation of analytic functions in small discs [
16]. The mentioned and other effective results connected to the universality of zeta-functions can be found in the survey paper [
17]. In this regard, we note that (
1) is implied by its short interval version, i.e., with
replaced by
. This is a standard notion in many aspects of analytic number theory.
From the point of view of effectivity, it is desirable to specify the shortest possible interval containing
such that
approximates a given analytic function. Thus, we arrive at the notion of universality theorems in short intervals
with
as
. A joint universality theorem for a short interval with generalized shifts has been obtained in [
18].
Denote by the class of tuples of real differentiable functions satisfying the following hypotheses:
are increasing functions on , , tending to ;
have continuous derivatives such that
where the functions
are monotonic,
, and, as
,
successively,
;
the estimates
, are valid.
For
, let
and
and
. In all subsequent theorems, we assume that
H satisfies
Then, in [
18], the following theorem has been obtained.
Theorem 1. Suppose that and that the length H lies in (2). For , let and . Then, for every , The universality of the Dirichlet series is a very useful property. Therefore, it is natural to ask if there is a possibility to extend the class of universal functions. One of the ways to achieve this is by using compositions of universal functions.
Denote by
the space of analytic
functions that has the topology of uniform convergence on compacta, and let
be the direct product of
r-copies of
. Hence, every element of
is the
r-dimensional vector
. Moreover, let
, where
is the zero-map, let
be the direct product of
r-copies of
, and let
be as above. In [
18], one theorem on the approximation of analytic functions by shifts
for some classes of operators
was obtained.
Moreover, we will use the vector notation
to mean the
r-tuple of admissible shifts, and let
Theorem 2. Suppose that ; the length H lies in (2), and is a continuous operator subject to the condition that, for every polynomial , the set is non-empty. Let and . Then, for every , Theorem 2 is theoretical; it is difficult to present examples of the operators F. The aim of the paper is to give other sub-classes of the operators in Theorem 2. We start with a modified Lipschitz class. Let be fixed positive numbers, and let .
Definition 1. The operator belongs to the class if the following hypotheses are satisfied:
For every polynomial and any sets , , the r-dimensional vector exists such that for ;
For every and , , a constant and sets exists such that Theorem 3. Suppose that ; the length H lies in (2), and . Let and . Then, for every inequality (3) is valid. It is very important is to be able to provide concrete examples of the investigated operators F, for ; it is not difficult.
Example 1. Let , , and denote the th derivative of . Define the operator by Now, we take an arbitrary polynomialand sets . We may take one of the components whose derivative coincides with , e.g., setwherewhere the constant is chosen so that for . Hence, in (4) satisfies the condition in Definition 1. To check condition , we apply the Cauchy integral theorem. Let . Then, there exists an open set U and such that . We take a simple closed contour C lying in and enclosing K. Then, the Cauchy integral formula shows that, for , , This can be bounded by for some constant . Thus, the condition holds with and , . Hence, .
For a given , denote the finite part of with imaginary parts being bounded by B, i.e., . Denote by the class of compact subsets of with connected complement, and by the class of continuous on functions that are analytic in the interior of ().
Theorem 4. Suppose that ; the length H lies in (2); and is a continuous operator so that for every polynomial , the set is not empty. Let and . Then, the same statement as in Theorem 2 holds true. Example 2. Define the operator by For a given polynomial , let If is with a large enough , then the latter collection lies in , and . Thus, F satisfies the hypothesis of Theorem 4.
Now, we will approximate the functions from certain subsets of
. Let
,
be distinct complex numbers, and
Theorem 5. Suppose that ; the length H lies in (2), and is a continuous operator such that . For , let , and on K. For , let K be an arbitrary compact subset of Δ, and . Then, the same statement as in Theorem 2 holds true. Example 3. Let , , , and For brevity, denote , and consider the equation Since , taking with other components , , we have that with . This shows that ; therefore, the operator F satisfies the condition of Theorem 5.
The last theorem is on the approximation of analytic functions from the set .
Theorem 6. Suppose that ; the length H lies in (2), and is a continuous operator. Let be a compact set, and . Then, the same statement as in Theorem 2 holds true. Proofs of Theorems 4–6 are of a probabilistic character, while that of Theorem 3 is direct and based on properties of the class . Moreover, as we mentioned above, in all of these theorems, the lower limit can be replaced with the limit for all but at most countably many , and we will prove it.
3. Proofs of Theorems 4–6
We will use limit theorems on the weakly convergence of probability measures in the space of analytic functions to prove Theorems 4–6.
Denote by
the Borel
-field of the topological space
. Let
l denote the unit circle on
, and let
for all
. Define the set
By Tikhonov theorem (see [
8] Theorem 5.1.4), the torus
is a compact topological Abelian group. Let
be the direct product of
, where
for all
. Then, again,
is a compact topological Abelian group. Thus, on
we can define the probability Haar measure
. This fact allows us to construct the probability space
. Denote by
the elements of
, and on the latter probability space, define the
-valued random element
by
where
Let
be the distribution of an element
, i.e.,
Then, in [
18], the following statement (Theorem 4, Lemma 5) has been obtained.
We will use one more notation to formulate this and other statements below. Let and P be probability measures defined on . The weak convergence of to P as ; we will denote by .
Lemma 2. Suppose that and the length H lies in (2). Definewhere, as before, Then, . Moreover, the support of the measure is the set .
In what follows, a property of preservation of weak convergence of probability measures under certain mappings will be useful. Let
P be a probability measure on
, and
a
-measurable mapping, i.e.,
. Then, the measure
P induces on
the unique probability measure
given by
Moreover, every continuous mapping is -measurable, and the following statement is valid.
Lemma 3. Suppose that and P, are probability measures on , and . Let be a continuous mapping. Then, as well.
A proof of the lemma can be found, for example, in [
20], Theorem 5.1.
Lemmas 2 and 3 imply the following lemma. For
, set
and
Lemma 4. Suppose that and the length H lies in (2). Then, , and the support of the measure is the set . Proof. Let the mapping
be given by
Then, is continuous, and . Therefore, in view of Lemmas 2 and 3, . Then, .
Let
and an open neighbourhood
G of
be arbitrary. Since
is continuous, the set
is open as well and contains an element
. Therefore,
. Thus, by Lemma 2,
Moreover, since
and
, we have
This and (
8) show that the support of
is the set
. □
Lemma 5. Under hypotheses of Theorem 4, , and the support of is the whole space .
Proof. Since the operator
F is continuous,
follows from the Lemma 4. Let
and its open neighbourhood
G be arbitrary. Then, the preimage
is also an open set. Suppose that
contains an element of the set
. Then, the Lemma 4 implies that
Since , this proves that the support of is . Thus, it remains to show that the hypothesis of the theorem implies that, for an open set , as well.
Recall the metric in
describing its topology of uniform convergence on compact sets. There is a sequence of embedded compact subsets
with connected complements such that
, and every compact set
is contained for some set
. Then, for
,
gives the desired metric in
.
Fix
and
satisfying
Let
and
G be its open neighbourhood. Since
, by Lemma 1, we can choose a polynomial
such that
This, together with (
9), shows that
. Therefore, if
is small enough, the polynomial
belongs to
G, and its preimage lies in
and lies in
. Hence,
. The lemma is proved. □
The definition of weak convergence of probability measures has equivalents in terms of various sets. We will use these equivalents in terms of some classes of sets, and we will present them in the following lemma (the proof of these given statements can be found, for example, in [
20] Theorem 2.1). Denote by
the boundary of a set
A. We say that
A is a continuity set of
P if
.
Lemma 6. Let P and , be probability measures defined on . Then, the following statements are equivalent:
;
, for every open set ;
, for every continuity set A of P.
Proof of Theorem 4. By Lemma 1, we can choose a polynomial
such that inequality (
7) holds. In view of Lemma 5, the polynomial
is an element of the support of the measure
. Hence,
where
Since
is an open set, by Lemma 5, and
and
of Lemma 6, we have
This, the definitions of
and
, and (
10), (
7) prove the inequality (
3) in Theorem 4.
To replace “lim inf” by “lim” in the inequality (
3) of the theorem, we observe that
is a continuity set of the measure
for all but at most countably many
. Actually, the boundary
lies in the set
Therefore, for different positive
and
,
and
do not intersect. Hence,
for at most countably many
, that is, the set
is a continuity set of the measure
for all but at most countably many
. Hence, by Lemma 5, and
and
of Lemma 6,
for all but at most countably many
. Moreover, (7) shows that
. Thus,
by (
10). This, (
11), and the definitions of
and
prove the assertion on density for at most countably many
. □
For
and
, define
Lemma 7. Under hypotheses of Theorem 5, . Moreover, the closure of the set lies in the support of .
Proof. Lemmas 2 and 3, and the continuity of the operator F show that .
We take an arbitrary element
and any open neighbourhood
of
g. Since
F is continuous,
is an open neighbourhood of some element of the set
. By Lemma 2, the set
is the support of the measure
. Therefore,
. Thus,
. Moreover,
Furthermore, the support of is a closed set; this shows that the support of is the closure of the set . By the hypothesis of the theorem, . Therefore, the closure of the set lies in the support of . □
Proof of Theorem 5. Let
. By Lemma 1, we find a polynomial
such that
By the hypothesis of the theorem, for
,
. Therefore,
for
. Thus, an application of Lemma 1 once more implies that we can choose a polynomial
such that
The function
. Thus, by Lemma 7, the closure of
lies in the support of
, and the function
belongs to the support of
. Hence, taking
we have
. This, Lemma 7, and
and
of Lemma 6 together with (
12) and (
13) prove the assertion on lower density of the theorem in the case
.
Then, similarly as in the case of
in the proof of Theorem 4, we have that
is a continuity set of the measure
for all but at most countably many
. Moreover, inequalities (
12) and (
13) show that
. Thus,
. This; Lemma 7; and
and
of Lemma 6 prove the assertion on density of the theorem in the case
.
Now, let
. Since
, we have by Lemma 7 that the set
is an open neighbourhood of an element of the support of the measure
. Thus,
. Therefore, by the first part of Lemma 7 and
,
of Lemma 6,
and the definitions of
and
prove the assertion in the case of lower density of the theorem.
For the proof of the second assertion of the theorem, it suffices to observe that the set is a continuity set of the measure for all but at most countably many . This; Lemma 7; and , of Lemma 6 give the assertion in the case of density of the theorem. □
Proof of Theorem 6. We use Lemmas 6 and 7 and repeat the arguments of the proof of Theorem 5 in the case . □