3.1. Formulation of Results
To use long exact cohomological exact sequences to describe the cohomology of classical modular Lie algebras with coefficients in simple modules, one needs complete information on the structures of the Weyl modules associated with these simple modules. As is known, in the general case, the structures of Weyl modules are well studied for affine dominant alcoves along the walls of the dominant Weyl chambers [
36] and for affine dominant alcoves close to them [
37]. Their highest weights are denoted by
These highest weights can be obtained by using the action of the Weyl group and translation to zero weight. Such descriptions of them were obtained in [
22] (pp. 9, 13). For convenience, we will list them in
Table 1 and
Table 2. For
Table 1 and
Table 2, the following notation are used:
is the maximal short root;
where
Note that
.
In [
22], the authors computed the ordinary cohomology of simple modules with dominant highest weights
For the corresponding restricted cohomology, the following results hold.
Theorem 1. Letbe a semisimple and simply connected algebraic group over an algebraically closed field of characteristicwhereis the Coxeter number, andbe the first Frobenius kernel ofConsider simple-modules with highest weightsand write them in the following form, as described inTable 1: where and Thenexcept in the following cases: - (a)
ifthen
- (i)
where
- (ii)
whereis even and
- (iii)
where
- (iv)
whereandis even;
- (b)
ifandthen
- (i)
where
- (ii)
whereandis even;
- (c)
ifandthen
- (i)
where
- (ii)
whereis even and
- (iii)
where
- (iv)
whereandis even;
- (d)
ifandthen
- (i)
where
- (ii)
whereandis even.
In the cases of the classical Lie algebras of types and the variability of the restricted cohomology cases for the simple modules with highest weights is slightly different from the general case. Therefore, below the results for them are formulated separately.
Theorem 2. Letbe a semisimple and simply connected algebraic group of typeover an algebraically closed field of characteristicwhereis the Coxeter number, andbe the first Frobenius kernel ofConsider simple-modules with highest weightsand write them in the following form, as described inTable 2: where and Thenexcept in the following cases: - (a)
if
then
- (i)
where
- (ii)
where
is even and
- (iii)
where
- (iv)
where
with
is even;
- (b)
if
then
- (i)
where
- (ii)
where
is even and
- (iii)
for
where
is even, - (iv)
for all
where
is even,
Here.
Theorem 3. Letbe a semisimple and simply connected algebraic group of typeover an algebraically closed field of characteristicwhereis the Coxeter number, andbe the first Frobenius kernel ofConsider simple-modules with highest weightsand write them in the following form, as described inTable 2: where and Thenexcept in the following cases: - (a)
ifandthen
- (i)
where
- (ii)
whereandis even;
- (b)
ifandthen
- (i)
where
- (ii)
whereis even and
- (iii)
where
- (iv)
whereis even and
- (ii)
whereandis even;
- (c)
if andthen
- (i)
where
- (ii)
whereandis even,
- (iii)
where
- (iv)
whereandis even,
- (v)
for allwhereis even,where
- (d)
if andthen
- (i)
where
- (ii)
whereandis even,
- (iii)
for allwhereis even,
- (e)
if andthen
- (i)
where
- (ii)
whereandis even,
- (iii)
for allwhereis even,
Hereand.
Theorem 4. Letbe a semisimple and simply connected algebraic group of typeorover an algebraically closed field of characteristicwhereis the Coxeter number, andbe the first Frobenius kernel ofConsider simple-modules with highest weightsand write them in the following form, as described inTable 1: where and Thenexcept in the following cases: - (a)
ifthen
- (i)
where
- (ii)
whereis even and
- (iii)
where
- (iv)
whereandis even;
- (b)
ifthen
- (i)
where
- (ii)
whereandis even,
- (iii)
wherefor allwhereis even,
- (c)
ifandthen
- (i)
where
- (ii)
for allwhereis even,
The following general result shows the importance of the cohomology of (restricted cohomology) in studying the connections between the cohomology of and with coefficients in simple restricted modules.
Theorem 5. Letbe a semisimple and simply connected algebraic group over an algebraically closed field of characteristicwhereis the Coxeter number,be the first Frobenius kernel ofand be the Lie algebra of Suppose thatis a simple module with the restricted highest weight. Then, for all
- (a)
if and only if
- (b)
if and only if
- (c)
if
Theorems 1–5 allow us to compare the structures of ordinary cohomology (cohomology for
), restricted cohomology (cohomology for
), and cohomology of the algebraic group associated with a given Lie algebra (cohomology for
). For example, comparison of Theorem 1 with the results on cohomology
obtained in [
22] yields the following result:
Corollary 1. Letbe a semisimple and simply connected algebraic group over an algebraically closed fieldof characteristicwhereis the Coxeter number,be the first Frobenius kernel ofand be the Lie algebra of Then, the nontrivial isomorphismof
-modules holds only in the following cases: - (a)
and
- (b)
and
- (c)
and
- (d)
and
Comparison of Theorems 2–4 with the results on cohomology
obtained in [
22] yields the following result:
Corollary 2. Letbe a semisimple and simply connected algebraic group over an algebraically closed fieldof characteristicwhereis the Coxeter number,be the first Frobenius kernel ofand be the Lie algebra of Then, the non-trivial isomorphismof
-modules holds only in the following cases: - (a)
and
- (b)
and
- (c)
and
- (d)
and
Using Theorem 1 and Statement (a) of Theorem 5, we obtain the following result on the connection between cohomology and :
Corollary 3. Letbe a semisimple and simply connected algebraic group over an algebraically closed fieldof characteristicwhereis the Coxeter number, andbe the first Frobenius kernel ofThen, the non-trivial isomorphismof-modules holds onlyforand.
Similarly, using Theorems 2–4 and Statement (a) of Theorem 5, we obtain the following result on the connection between cohomology and :
Corollary 4. Letbe a semisimple and simply connected algebraic group over an algebraically closed fieldof characteristicwhereis the Coxeter number, andbe the first Frobenius kernel ofThen, the nontrivial isomorphismsof-modules holds only in the following cases:
- (a)
and
- (b)
and
- (c)
and
- (d)
and
- (a)
and
Corollaries 1 and 3 immediately imply the following result:
Corollary 5. Letbe a semisimple and simply connected algebraic group over an algebraically closed fieldof characteristicwhereis the Coxeter number, be the Lie algebra of andbe the first Frobenius kernel of Then, the non-trivial isomorphismsof-modules hold onlyforand.
The existence of these isomorphisms was previously established in [
22] (p. 7). Corollary 5 establishes that for simple modules
there are no other such non-trivial isomorphisms.
Similarly, the following result immediately follows from Corollaries 2 and 4:
Corollary 6. Letbe a semisimple and simply connected algebraic group over an algebraically closed fieldof chacteristicwhere. is the Coxeter number, be the Lie algebra of andbe the first Frobenius kernel of Then, the non-trivial isomorphismsof-modules hold only in the following cases:
- (a)
and
- (b)
and
- (c)
and
- (d)
and
- (e)
and
3.2. Proof of the Results
Proof of Theorem 1. We will use the algorithm for calculating restricted cohomology with coefficients in simple modules given at the end of
Section 2 for
with
Let us calculate
and
According to
Table 1, for all
and
Now, let us give the structure of
as a
-module. Since in the restricted region the representation theories
and
are equivalent, then
has the same structure as a
-module and a
-module. Therefore, by Statement (
a) of Lemma 4.1 in [
22] (p. 3870),
for all
as
-module.
The next two steps of the algorithm for calculating the cohomology will be done separately in the corresponding statements of the theorem. □
Proof of Statement (a) of Theorem 1. We will calculate
and
simultaneously. By (7),
for all
By (6)
, for all
Then, by (4) and (5), for all
Let
Then, using the induction on
from (8), we obtain
for all
We use the induction on
If
then, by (9),
since
. Suppose that
for all
where
and prove that
. By (9),
By the induction hypothesis,
for all
Therefore,
for all
Thus,
for all
and for all
Now, let
Then, using (8), we see that in this case also (9) holds. If
then, by (9),
since
. Suppose that
for all
where
and
We prove that
if
Using (9), we get that
if
By the induction hypothesis,
if
Therefore,
if
Thus,
for all
and for
This proves the sub-statement (
i).
If
then, by (8), in this case also the Formula (9) holds. Let
then, by (9),
if
If
is even, then, by (3),
is non-trivial, otherwise
. Suppose that
for all
if
Prove that
if
Using (9), we get that
if
By the induction hypothesis,
if
Therefore,
if
Thus,
for all
if
If
is even, then, by (3),
is non-trivial, otherwise
. So, we get the sub-statement (
ii).
If
then (8),
for all
By the sub-statement (
ii) of this Statement (
a),
if
Then, by (10),
for all
By (3),
and
are non-trivial. Therefore, the sub-statements (
iii) hold.
Finally, let
Then, using (8), we see that in this case (10) also holds. Let
then, by (10),
if
If
is even, then, by (3), both summands of the sum of the left-hand side of the last isomorphism are nontrivial, otherwise both of them are trivial. Suppose that
for all
if
Prove that
if
Using (10), we get that
if
By the induction hypothesis,
if
Therefore,
if
Thus,
for all
if
If
is even, then, by (3), all summands of the sum of the left-hand side of the last isomorphism are non-trivial, otherwise they are all trivial. Therefore, the sub-statement (
iv) is true. The proof of the statement (
a) is complete.
If then the situation is slightly different from the previous case. The following statements cover them. □
Proof of Statement (b) of Theorem 1. In this case, and . Note that
Let Since we will use the Formula (4) for . Using (4) and (7), we get By the Statement (a), . Therefore, .
Let
By (7),
and by the Statement (
a),
Moreover, according to (3),
Because
then, for
the short exact sequence (5) splits. So, we get an isomorphism
This is the sub-statement (i).
If then by (5) for To avoid repetition, here and in what follows we will omit all the details of the induction process on . Using the sub-statement (i) of this Statement (b) and the induction on we get By (3), all summands of this sum are non-trivial if is even, otherwise they are all trivial. Hence, the sub-statement (ii) is true. □
Proof of Statement (c) of Theorem 1. Note that , . and
Let Using (4) and (7), we get . By the Statement (b), . Therefore, .
Let
We will use the short exact sequence (5) for
. By (7),
Since
then, by the Statement (
b),
. Moreover according to (3),
Then, using the short exact sequence (5), we get an isomorphism
This is the sub-statement (i).
If . then by (5) for . Using the sub-statement (i) of this Statement (c) and the induction on we get By (3), all summands of this sum are non-trivial if is even, otherwise they are all trivial. Hence, the sub-statement (ii) is true.
Now let Then by (5) for . Using the sub-statement (ii) of this Statement (c) and the induction on . we get .
By (3), all summands of this sum are non-trivial. So, we get the sub-statement (iii).
Finally let Then, by (5) for Using the sub-statement (iii) of this Statement (c) and the induction on we get By (3), all summands of this sum are non-trivial if is even, otherwise they are all trivial. Hence, we have obtained sub-statement (iv). □
Proof of Statement (d) of Theorem 1. Is similar to Proof of Statement (b) of Theorem 1. We only note that, in this case, and . □
Proof of Theorems 2–4. First, we will calculate
and According to
Table 2, for all
, except in the case where
and
and
Now, let us give the structure of
as a
-module. Since in the restricted region the representation theories
and
are equivalent, then
has the same structure as an
. -module and a
-module. Therefore, by the statements (
b)–(
d) of Lemma 4.1 in [
22] (p. 3870),
and there exist the following short exact sequences:
and
for all
The next two steps of the algorithm for calculating the cohomology will be done separately in the corresponding statements. Since the proofs of Theorems 2–4 are similar, we will only illustrate in more detail the proofs of Statements of Theorem 3, which is more variable. □
Proof of Statement (a) of Theorem 3. In this case, and . By (12), By (6), and by (11), .
Let . Since for all then .
If
then, by Statement (
b) of Theorem 1,
So, by (4),
This is the sub-statement (i).
Let . In this case, there is only one value . Then, by Statement (b) of Theorem 1, . Therefore, .
If
Then, by Statement (
b) of Theorem 1,
By (3), all summands of this sum are non-trivial if is even, otherwise they are trivial. Hence, we have obtained sub-statement (ii). □
Proof of Statement (b) of Theorem 3. In this case,
and
. By (12),
By (6), and by (11), .
Let . Since for all then .
If
then, by Statement (
a) of Theorem 1,
So, by (4),
This is the sub-statement (i).
Let . Then, by Statement (a) of Theorem 1, . Therefore, by (4), This cohomology is non-trivial if is even, and is trivial otherwise. So, we get the sub-statement (ii).
If then, by Statement (a) of Theorem 1, . Therefore, by (4), .
If
then, by Statement (
a) of Theorem 1,
Therefore, by (4),
This is the sub-statement (iii).
If
then, by Statement (
b) of Theorem 1,
If is even, then, by (3), all summands of the sum of the left-hand side of the last isomorphism are non-trivial, otherwise they are all trivial. Therefore, the sub-statement (iv) is true.
Finally, let
. then, by Statement (
b) of Theorem 1,
If is even, then, by (3), all summands of the sum of the left-hand side of the last isomorphism are non-trivial, otherwise they are all trivial. Therefore, the sub-statement (v) is true. □
Proof of Statement (c) of Theorem 3. In this case,
and
The long cohomological sequences corresponding to the short exact sequences (13) and (14) yield the exact sequences
respectively.
Let
By Statement (
a) of Theorem 1 and Statement (
b) of this Theorem 3,
and
Then it follows from the exactness of the sequences (15) and (16) that
. Therefore, by (4),
Let
We use the induction on
If
, then
and, by Statement (
a) of Theorem 1 and Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (15) that
Therefore, by (4),
Now suppose that
for all
By Statement (
a) of Theorem 1,
and
. By the induction hypothesis,
. Then the exactness of the sequence (16) yields
Hence, by (4), So, for all which proves the sub-statement (i).
Let
. We will use induction on
If
then by Statement (
a) of Theorem 1,
and
By Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (15) that
Now suppose that
for all
By Statement (
a) of Theorem 1,
and
By the induction hypothesis,
. Then the exactness of the sequence (16) yields
So, for all which proves the sub-statement (ii).
Let
If
then by Statement (
a) of Theorem 1,
and
By Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (15) that
Now suppose that
for all
By Statement (
a) of Theorem 1,
and
By the induction hypothesis,
Then the exactness of the sequence (16) yields
So, for all which proves the sub-statement (iii).
Let
. If
then by Statement (
a) of Theorem 1,
and
By Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (15) that
Now suppose that
for all
By Statement (
a) of Theorem 1,
and
By the induction hypothesis,
Then the exactness of the sequence (16) yields
So,
for all
which proves the sub-statement (
iv).
Let
. If
then by Statement (
a) of Theorem 1,
and
By Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (15) that
Since
using (5), we get
where
Now suppose that
for all
where
. By Statement (
a) of Theorem 1,
and
By the induction hypothesis,
Then the exactness of the sequence (16) yields
So,
for all
which proves the sub-statement (
v). □
Proof of Statement (d) of Theorem 3. In this case,
and
Let
By Statement (
a) of Theorem 1 and Statement (
b) of this Theorem 3,
and
. Then it follows from the exactness of the sequence (16) that
. Therefore, by (4),
.
Let Then, by Statement (a) of Theorem 1 and Statement (b) of this Theorem 3, and Then it follows from the exactness of the sequence (16) that Therefore, by (4), We get the sub-statement (i).
Let
Then, by Statement (
a) of Theorem 1,
and by Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (16) that
So, we get the sub-statement (ii).
Let
Then, by Statement (
a) of Theorem 1,
and by Statement (
b) of this Theorem 3,
Then it follows from the exactness of the sequence (16) that
So, we get the sub-statement (iii). □
Proof of Statement (e) of Theorem 3. In this case,
and
Let
By Statement (
a) of Theorem 1 and Statement (
b) of this Theorem 3,
and
. Then it follows from the exactness of the sequence (16) that
. Therefore, by (4),
.
Let
If
, then by Statement (
b) of Theorem 1,
and
By Statement (
d) of this Theorem 3,
Then it follows from the exactness of the sequence (15) that
Therefore, by (4),
Now suppose that
for all
where
. By Statement (
c) of Theorem 1,
and
By the induction hypothesis,
. Then the exactness of the sequence (16) yields
Hence, by (4), So, for all which proves the sub-statement (i).
The proofs of the sub-statements (ii) and (iii) are similar to the proofs of the sub-statements (iv) and (v) of Statement (c) of this Theorem 3. □
Proof of Theorem 5. By Theorem 1 in [
38] (p. 38), for all
there is an isomorphism
of
-modules, where
is a simple
-modules with the restricted highest weight. □
Proof of Statement (a) of Theorem 5. Necessity. If
then, by (17),
Sufficiency. If
then, by (17),
□
Proof of Statement (b) of Theorem 5. Necessity. If
then, by (17),
Sufficiency. If
then, by (17),
□
Proof of Statement (c) of Theorem 5. If
then, by (17).
□
Proof of Corollary 1. If
then by Theorem 1,
and, by Theorem 1 in [
22] (p. 6),
. Therefore, in this case, there is no non-trivial isomorphism
.
Let
and
If the cohomology
and
are non-trivial, then, according to Theorem 1 in [
22] (p. 6), the cohomology
is isomorphic to the cohomology
, but, by Theorem 1 of this paper, the cohomology
is isomorphic to the cohomology
It is known that the cohomology
is a
-module with a trivial action of
[
39] (pp. 173–174). According to (3), the cohomology
is not a trivial as
-module. Consequently, in this case, too, a non-trivial isomorphism
does not exist.
If and then arguing as in the previous case, we obtain that, in the non-trivial cases, the cohomology and are not isomorphic.
Now, let
and
Then, by Theorem 1,
and, by Theorem 1 in [
22] (p. 6),
Therefore, we get the non-trivial isomorphism
Thus, we have Statement (
a).
Let
and
If
then by Theorem 1,
and, by Theorem 1 in [
22] (p. 6),
. If
then, by Theorem 1,
and, by Theorem 1 in [
22] (p. 7),
Therefore, we get the non-trivial isomorphism
Thus, we have Statement (
b). If
then arguing as in the proof of Statement (
a), we obtain that the required non-trivial isomorphism does not exist.
Let
and
If
then by Theorem 1,
and, by Theorem 1 in [
22] (p. 7),
. If
then, by Theorem 1,
and, by Theorem 1 in [
22] (p. 7),
Therefore, we get the non-trivial isomorphism
Thus, we have Statement (
c). In other cases, there are no non-trivial isomorphisms, since
and
have different
-module structures.
Let
and
If
then by Theorem 1,
and, by Theorem 1 in [
22] (p. 7),
. If
then, by Theorem 1,
and, by Theorem 1 in [
22] (p. 7),
Therefore, we get the non-trivial isomorphism
Thus, we have Statement (
d). Since
and
have different
-module structures, no other nontrivial isomorphisms appear. □
Proof of Corollary 2. Is similar to that of Corollary 1. □
Proof of Corollary 3. Follows from Theorem 1 and Statement (a) of Theorem 5. □
Proof of Corollary 4. Follows from Theorems 2–4 and Statement (a) of Theorem 5. □