2.1. The Function of the Minimum Norm with a Given Set of Fourier Coefficients
Consider the following problem:
Find the function of the minimum norm
on the class of integrable functions
with the given first
Fourier coefficients
Define the points
on the interval
and for an arbitrary constant
consider the vector function
Note that the coordinates of F are the Fourier coefficients of the locally constant function. Thus, the question is whether we can find the constant C and the angles so that .
We introduce on the equivalence relation with and . The function F takes the same value on elements of the same equivalence class. Consider the factor space .
Theorem 1. The mapping is a surjection.
Proof. Put
,
,
,
. Then, the Jacobi matrix of the mapping
F takes the form
Note that C is a constant that scales an image of .
For
, the Jacobi matrix of the mapping
is
Since an arbitrary string of n real elements sets the values of a trigonometric polynomial of order n at points , and the rows of this matrix form the basis values at the same points, the rank of this map is when .
In the space
, we consider the hypersurface
. We show that in each direction
in space
there exist no more than two sets
for which
. Consider the trigonometric polynomial
, corresponding to the derivative in the direction
, and find the roots of this polynomial. There exist at most
such roots.
Let there be exactly of such roots. In this case, the set corresponds to a trigonometric polynomial of order n with roots . The set represents the roots of a new polynomial obtained from the first polynomial by a change of sign.
If there exist fewer than roots, then we get the roots of the given polynomial and are the roots of a polynomial obtained from the first one by change of sign.
This means that in any direction the derivative of the function has no more than two zeros. Thus, is a convex hypersurface.
Note that the hypersurface is symmetric about the origin by construction, because and compact, since each coordinate is bounded in .
Thus, we have the following:
The Jacobian is not zero on the hypersurface with and .
The Jacobian is zero on the hypersurface on a subset of dimension , and the degeneration of the map occurs with .
Since the mapping is continuous, its image is closed on the hypersurface . Item 1 implies that this hypersurface has dimension . Item 2 yields that the dimension of the boundary of this image is . Consequently, the image of is a manifold of dimension without an edge.
Consequently, the image of is a convex surface that is homotopy equivalent to the sphere .
Therefore, for any point exist a number and a set such that . □
Corollary 1. For each set of Fourier coefficients, there exists a piecewise constant, constant modulo function with a given set of first coefficients.
Proof. Since the components of the vector function
introduced in Theorem 1 are the Fourier coefficients of the piecewise constant function
in accordance with Theorem 1, we obtain the proof of this statement. □
Theorem 2. For any set there exists a unique function (Equation (1)) that minimizes the norm . Proof. In accordance with Corollary 1, for a given set of Fourier coefficients , we choose a piecewise constant, where is the minimal possible number from the preimages .
Assume that there exists a function less than or equal to the norm of , with the same set of coefficients.
Consider the difference of two functions , with a given set of first Fourier coefficients. Since the first Fourier coefficients are 0, this function has the form , where is a function that is holomorphic in the unit circle. Consequently, in accordance with the principle of the argument, the difference changes sign not fewer than times. Since , we have , , , , , . That is, the difference changes sign no more than times. The contradiction confirms that the function has a minimal norm.
Uniqueness of this function on the class of functions of the form of Equation (
1) follows from the same considerations. Let there be another piecewise-constant function with a constant module
with the same first Fourier coefficients in accordance with Corollary 1. Then,
and from the already proved, it follows that the set
for the function
coincides with the corresponding set for
. □
From Theorems 1 and 2, it follows that F is a global homeomorphism and C is the minimum norm of the function, the first of the Fourier coefficients of which are .
Let us give examples illustrating the results of Theorem 2 for the case
. We construct piecewise constant functions that provide the minimum norm for given trigonometric polynomials. The examples are constructed by selecting the values
,
so that the ratio of the Fourier coefficients of a constant modulo function is the same as that of the original polynomial.
Figure 1 and
Figure 2 show the graphs of both approximate and corresponding constant modulo functions with
and
, respectively.
Consider the function
and the sequence
,
,
. Then, we have functions of the type (
1)
,
of minimal norm
for polynomials
.
This leads us to the following statements.
Corollary 2. , ().
Proof. Assume the contrary. Since, for each
n,
is a function of the minimum possible norm for a given set of Fourier coefficients of the function
g, the sequence of norms
is marorized by the sequence of norms
. In addition, since
is constructed according to a larger number of given Fourier coefficients than
,
. Consequently, the sequence
is monotone and bounded above, that is, converges. Let
, (
). By assumption,
. Consider
The function realizes the minimal distance from the function to a convex set of functions modulo less than D. Consider the finite sum of the Fourier series for , . Then, there is such that for any , . Consequently, any finite-dimensional subset of a convex set of functions modulo less than D is at a distance not less than from . Therefore, the Fourier coefficients are separated from the coefficients starting from a certain number. This contradicts the assumption that the first Fourier coefficients for and coincide. □
We now easily infer the following.
Corollary 3. by the norm , () ⇔.
Examples from [
4] show the convergence of polynomials to step functions, which are solutions to the problem as the degree of polynomials tends to
∞.
2.3. The Function of the Minimum Norm with a Given Set of Fourier Coefficients
Consider the following problem.
On the class of non-negative integrable functions
with the given
Fourier coefficients
find the function of the minimum norm
.
Here, is the Kronecker -function.
Theorem 3. For any set , there is a unique function of the form in Equation (2), which is a solution of the formulated problem. Proof. The proof of the statement is based on the same considerations as in the case of the problem for the norm .
Existence. As in Theorem 1, we show the degeneration of the mapping image boundary.
For
, the map Jacobian is non-degenerate, since it is a multiple of the determinant of the Vandermond matrix
. The Jacobi matrix of the mapping
is a block matrix of the form
This matrix is non-degenerate if and only if the Jacobi matrix of the mapping complexified with the affinor is degenerate. This is true for , or for , . The image of is a subset of dimension with boundary of dimension of space . Then, .
Further, similar to the proof of Theorem 2, we prove the uniqueness of the pre-image for the mapping .
Assume that there exist two different solutions and . Consider , . On the one hand, for some , the function has at least sign changes. On the other hand, has at most sign changes for any K. We arrive at a contradiction. □
We now consider the problem of finding the function of the minimum norm satisfying the conditions
- (1)
; and
- (2)
, , , .
Corollary 4. For any set , there exists a function of the form in Equation (3) satisfying Conditions (1) and (2). We construct the function from Theorem 3 by the set of coefficients and the function by the set of coefficients and select so that .
Note that for
the solution to the last problem is
[
12].
Example. Consider the polynomial . Then, the first term in Corollary 4 is of the form , and the second equals . We have and .