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Article

Proportional Itô–Doob Stochastic Fractional Order Systems

by
Abdellatif Ben Makhlouf
1,*,
Lassaad Mchiri
2,
Hakeem A. Othman
3,
Hafedh M. S. Rguigui
3 and
Salah Boulaaras
4
1
Department of Mathematics, College of Science, Jouf University, P.O. Box 2014, Sakaka 72388, Saudi Arabia
2
ENSIIE, University of Evry-Val-d’Essonne, 1 Square de la Résistance, 91025 Évry-Courcouronnes, CEDEX, France
3
Department of Mathematics, AL-Qunfudhah University College, Umm Al-Qura University, Al Qunfudhah 28821, Saudi Arabia
4
Department of Mathematics, College of Sciences and Arts, ArRass, Qassim University, Almelida 51452, Saudi Arabia
*
Author to whom correspondence should be addressed.
Mathematics 2023, 11(9), 2049; https://doi.org/10.3390/math11092049
Submission received: 23 March 2023 / Revised: 21 April 2023 / Accepted: 23 April 2023 / Published: 26 April 2023

Abstract

:
In this article, we discuss the existence and uniqueness of proportional Itô–Doob stochastic fractional order systems (PIDSFOS) by using the Picard iteration method. The paper provides new results using the proportional fractional integral and stochastic calculus techniques. We have shown the convergence of the solution of the averaged PIDSFOS to that of the standard PIDSFOS in the context of the mean square and also in probability. One example is given to illustrate our results.

1. Introduction

Fractional calculus has attracted much more attention over the past three decades, due to its applications in many fields of science and engineering. It provides several potentially useful tools for solving differential and integral equations.
The concept of fractional calculus occurred from a question posed in 1695 by L’Hôpital to Gottfried Wilhelm Leibniz, who wanted to understand the meaning of Leibniz’s notation d m d ς m G ( ς ) if m = 1 2 . In his answer, dated 30 September 1695, Leibniz wrote to L’Hôpital as follows: “It is an apparent paradox from which, one day, useful consequences will be drawn.” Later, many definitions of fractional derivatives were formulated by Euler, Lagrange, Laplace, Lacroix, Fourier, Liouville, and other research scientists. The theory of fractional analysis has many applications, such as the circulation of fluids, dynamic processes, telegraph equations, electrical networks, signal processing, etc. (see [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]). Furthermore, fractional calculus can be applied to solve some real-world problems in the engineering, biological, and physical disciplines (see [2,4,6]).
One of the most important classes of fractional derivative is the proportional and Caputo-proportional fractional derivatives. Many researchers have investigated the proportional and Caputo-proportional fractional differential equations; for more details, see [17,18,19,20,21,22]. Some inequalities were studied within the proportional fractional operators [19,21], and [23] discussed the proportional derivatives of a function with respect to another function. Itô–Doob stochastic fractional order systems (IDSFOS) are an important type of fractional integral equations; this class of equations receives much more attention (see [24,25,26,27]). In [25], Abouagwa et al. have studied the averaging principle of IDSFOS with non-Lipschitz coefficients. In [24], the authors discussed the criterion for well-posedness (existence and uniqueness) and mean square stability of solutions to non-Lipschitz IDSFOS. The averaging principle is an important tool to approximate the solutions of the systems driven by differential equations which result from mathematics, mechanics, control, and other fields of sciences. The general idea of the averaging principle theorem is as follows: the solutions of the original system can be approximated by the corresponding solutions to the standard system, in both the senses of the mean square and probability (see [25,28,29,30,31,32,33,34]).
Taking into account the discussion presented above, this article is devoted to the analysis and study of the averaging principle for PIDSFOS. In the literature, several works which are interested in the averaging principle focus on the field of stochastic differential equations. In the literature, the averaging principle of fractional stochastic equations is a new theory, and in particular, there is no existing paper which studies the averaging principle for PIDSFOS. Motivated by the previous work in [25], this paper investigated the problem of the averaging principle of the solution for the proportional fractional integral. The main contributions of our work are as follows:
Unlike other works in the literature, this paper presents a new theory by the proportional fractional integral.
We study the existence and uniqueness of the solutions of PIDSFOS using the Picard iteration technique.
We discuss the convergence of the solution of the averaged PIDSFOS towards that of the standard PIDSFOS in the sense of the mean square.
This paper is organized as follows. Some preliminary notions are presented in Section 2. Section 3 is devoted to the existence and uniqueness results using the Picard iteration method. Section 4 investigated the convergence of the solution of the averaged PIDSFOS to the solution of the standard PIDSFOS in the sense of the mean square and also in probability. Finally, in Section 5, we illustrate our results with a theoretical example.

2. Preliminaries and Definitions

Let R = { X , F , ( F ϖ ) ϖ 1 , P } be a complete probability space.
Definition 1 
([22]). For ν 0 , 1 ,   δ > 0 , the GPF integral of f of order δ is
I a δ , ν f μ = 1 ν δ Γ δ a x exp ν 1 ν μ κ μ κ δ 1 f κ d κ .
Consider the following PIDSFOS:
z ( ϖ ) = θ + 0 ϖ τ q , z ( q ) d q + 0 ϖ ϑ 1 q , z ( q ) d W ( q ) + ϰ a ϰ 0 ϖ exp a 1 a ϖ q ϖ q ϰ 1 ϑ 2 q , z ( q ) d q .
with θ R n , 1 2 < ϰ < 1 , ϖ [ 0 , T ] .
Set the following assumptions:
  • H 1 : There is K ¯ > 0 such that
| τ ( η , θ 1 ) τ ( η , θ 2 ) | 2 | ϑ 1 ( η , θ 1 ) ϑ 1 ( η , θ 2 ) | 2 | ϑ 2 ( η , θ 1 ) ϑ 2 ( η , θ 2 ) | 2 K ¯ | θ 1 θ 2 | 2 ,
for all ( η , θ 1 , θ 2 ) [ 0 , T ] × R n × R n .
  • H 2 : There is K > 0 such that
| τ ( η , θ ) | 2 | ϑ 1 ( η , θ ) | 2 | ϑ 2 ( η , θ ) | 2 K ( 1 + | θ | 2 ) ,
for all ( η , θ ) [ 0 , T ] × R n .

3. Existence and Uniqueness Results

Theorem 1. 
Suppose that H 1 and H 2 hold. Then, there is a unique solution z ( ϖ ) of Equation (1) such that z ( ϖ ) M 2 [ 0 , T ] ; R n .
Before showing Theorem 1, we present the following useful lemma.
Lemma 1. 
Suppose that H 2 holds. If z ( ϖ ) is a solution of Equation (1), then
E ( sup 0 ϖ T | z ( ϖ ) | 2 ) ( 1 + 3 E | θ | 2 ) e 3 K T ( T + 4 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 ) .
In particular, z ( ϖ ) M 2 [ 0 , T ] ; R n .
Proof. 
For any integer n N , let the stopping time ς n = T i n f { t [ 0 , T ] ; | z ( ϖ ) | n } . It is easy to see that ς n T a.s. Set z n ( ϖ ) = z ( ϖ ς n ) , for ϖ [ 0 , T ] . Then, z n ( ϖ ) verifies
z n ( ϖ ) = θ + 0 ϖ τ s , z n ( s ) 1 [ 0 , ς n ] ( s ) d s + 0 ϖ ϑ 1 s , z n ( s ) 1 [ 0 , ς n ] ( s ) d W ( s ) + ϰ a ϰ 0 ϖ exp a 1 a ϖ ς n s ϖ ς n s ϰ 1 ϑ 2 s , z n ( s ) 1 [ 0 , ς n ] ( s ) d s .
By the Cauchy–Schwartz inequality and assumption H 2 , we derive
| z n ( ϖ ) | 2 3 | θ | 2 + 3 ϖ 0 ϖ | τ s , z n ( s ) | 2 d s + 3 | 0 ϖ ϑ 1 s , z n ( s ) 1 [ 0 , ς n ] ( s ) d W ( s ) | 2 + 3 ϰ 2 a 2 ϰ 0 ϖ exp 2 a 1 a ϖ s ϖ s 2 ϰ 2 d s 0 ϖ | ϑ 2 s , z n ( s ) | 2 d s 3 | θ | 2 + 3 ϖ 0 ϖ | τ s , z n ( s ) | 2 d s + 3 | 0 ϖ ϑ 1 s , z n ( s ) 1 [ 0 , ς n ] ( s ) d W ( s ) | 2 + 3 ϰ 2 a 2 ϰ 0 ϖ ϖ s 2 ϰ 2 d s 0 ϖ | ϑ 2 s , z n ( s ) | 2 d s 3 | θ | 2 + 3 K ϖ 0 ϖ ( 1 + | z n ( s ) | ) 2 d s + 3 | 0 ϖ ϑ 1 s , z n ( s ) 1 [ 0 , ς n ] ( s ) d W ( s ) | 2 + 3 ϰ 2 K a 2 ϰ 2 ϰ 1 ϖ 2 ϰ 1 0 ϖ ( 1 + | z n ( s ) | ) 2 d s .
Hence, using Theorem 7.2 (p. 40 in [35]) and assumption H 2 , we have
E ( sup 0 s ϖ | z n ( s ) | 2 ) 3 E | θ | 2 + 3 K T 0 ϖ ( 1 + E | z n ( s ) | 2 ) d s + 12 E 0 ϖ | ϑ 1 s , z n ( s ) | 2 1 [ 0 , ς n ] ( s ) d s + 3 ϰ 2 K a 2 ϰ 2 ϰ 1 T 2 ϰ 1 0 ϖ ( 1 + E | z n ( s ) | 2 ) d s 3 E | θ | 2 + 3 K ( T + 4 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 ) 0 ϖ ( 1 + E | z n ( s ) | 2 ) d s .
Therefore,
1 + E sup 0 s ϖ | z n ( s ) | 2 1 + 3 E | θ | 2 + 3 K T + 4 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 ϖ 1 + E ( sup 0 l s | z n ( l ) | 2 ) d s .
By the Gronwall inequality, we obtain
1 + E sup 0 s ϖ | z n ( s ) | 2 1 + 3 E | θ | 2 e 3 K T ( T + 4 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 ) .
Finally, we obtain the required inequality by letting n . □
Now, we will show Theorem 1.
Proof of Theorem 1 
Uniqueness:– Consider z ( ϖ ) and z ¯ ( ϖ ) to be two solutions of Equation (1).
  • According to Lemma 1, z ( ϖ ) and z ¯ ( ϖ ) belong to M 2 [ 0 , T ] ; R n . Thus,
z ( ϖ ) z ¯ ( ϖ ) = 0 ϖ τ s , z ( s ) τ s , z ¯ ( s ) d s + 0 ϖ ϑ 1 s , z ( s ) ϑ 1 s , z ¯ ( s ) d W ( s )
+ ϰ a ϰ 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ( s ) ϑ 2 s , z ¯ ( s ) d s .
Using the Hölder inequality, Theorem 7.2 (p. 50 in [35]), and H 1 , proceeding as the proof of Lemma 1, we derive
E sup 0 s ϖ | z ( s ) z ¯ ( s ) | 2 3 K ¯ T + 4 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 ϖ E sup 0 l s | z ( l ) z ¯ ( l ) | 2 d s .
  • By the Gronwall inequality, we can obtain E sup 0 s ϖ | z ( s ) z ¯ ( s ) | 2 = 0 . Hence, z ( ϖ ) = z ¯ ( ϖ ) , a.s.
  • Existence:– Set z 0 ( ϖ ) = θ . The iterative Picard method is defined by the sequence ( z n ) n 1 as follows:
z n ( ϖ ) = θ + 0 ϖ τ s , z n 1 ( s ) d s + 0 ϖ ϑ 1 s , z n 1 ( s ) d W ( s ) + ϰ a ϰ 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z n 1 ( s ) d s .
It is obvious to see that θ M 2 [ 0 , T ] ; R n . Moreover, it is not hard to see that z n ( ϖ ) M 2 [ 0 , T ] ; R n by induction, because by Equation (9), we have
E | z n ( ϖ ) | 2 C 1 + 4 K T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 ϖ E | z n 1 ( s ) | 2 d s ,
where C 1 = 4 E | θ | 2 + 4 K T T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 .
  • By Equation (10), it yields that for any k 1 :
    max 1 n k E | z n ( ϖ ) | 2 C 1 + 4 K T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 ϖ max 1 n k E | z n 1 ( s ) | 2 d s C 1 + 4 K T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 ϖ E | θ | 2 + max 1 n k E | z n ( s ) | 2 d s C 2 + 4 K T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 ϖ max 1 n k E | z n ( s ) | 2 d s ,
    where C 2 = C 1 + 4 K T T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 E | θ | 2 .
  • Using the Gronwall inequality, we have
    max 1 n k E | z n ( ϖ ) | 2 C 2 e 4 K T T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 .
    Using the fact that k is arbitrary, this implies
    E | z n ( ϖ ) | 2 C 2 e 4 K T T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 ,
    for all 0 ϖ T , n 1 .
  • Note that
    | z 1 ( ϖ ) θ | 2 3 | 0 ϖ τ s , z 0 ( s ) d s | 2 + 3 | 0 ϖ ϑ 1 s , z 0 ( s ) d W ( s ) | 2 + 3 ϰ 2 a 2 ϰ | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z 0 ( s ) d s | 2 .
    Applying the expectation and using assumption H 1 , we derive
    E | z 1 ( ϖ ) θ | 2 3 K ϖ 2 1 + E | z 0 ( ϖ ) | 2 + 3 K ϖ 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 1 + E | z 0 ( ϖ ) | 2 C ,
    where
    C = 3 K T T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 1 + E | z 0 ( ϖ ) | 2 .
    Let us claim that for n 0 ,
    E | z n + 1 ( ϖ ) z n ( ϖ ) | 2 C M ϖ n n ! ,
    for 1 ϖ T , where M = 3 K ¯ T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 .
  • We will show that Equation (14) holds true by induction. Using Equation (13), we can see that Equation (14) holds when n = 0 .
  • Suppose that Equation (14) holds for some n 0 . We will show that Equation (14) still holds for n + 1 .
  • We can see that
    | z n + 2 ( ϖ ) z n + 1 ( ϖ ) | 2 3 | 0 ϖ τ s , z n + 1 ( s ) τ s , z n ( s ) d s | 2 + 3 | 0 ϖ ϑ 1 s , z n + 1 ( s ) ϑ 1 s , z n ( s ) d W ( s ) | 2 + 3 ϰ 2 a 2 ϰ | 0 ϖ exp a 1 a ϖ q ϖ q ϰ 1 ϑ 2 q , z n + 1 ( q ) ϑ 2 q , z n ( q ) d q | 2 .
Applying the expectation to Equation (15), by H 1 and Equation (14), we have
E | z n + 2 ( ϖ ) z n + 1 ( ϖ ) | 2 3 K ¯ ϖ + 1 + ϰ 2 ϖ 2 ϰ 1 a 2 ϰ 2 ϰ 1 E 0 ϖ | z n + 1 ( s ) z n ( s ) | 2 d s M 0 ϖ C [ M s ] n n ! d s C [ M ϖ ] n + 1 ( n + 1 ) ! .
Thus, Equation (14) holds for all n 0 . Furthermore, if we replace n in Equation (15) with n 1 , it yields that
sup 0 ϖ T | z n + 1 ( ϖ ) z n ( ϖ ) | 2 3 K ¯ T + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 T | z n ( s ) z n 1 ( s ) | 2 d s + 3 sup 0 ϖ T | 0 ϖ ϑ 1 s , z n ( s ) ϑ 1 s , z n 1 ( s ) d W ( s ) | 2 .
Applying the expectation to Equation (17), using Theorem 7.2 (p. 40 in [35]) and Equation (14), we obtain
E sup 0 ϖ T | z n + 1 ( ϖ ) z n ( ϖ ) | 2 3 K ¯ T + 4 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 T E | z n ( s ) z n 1 ( s ) | 2 d s 4 M 0 T C [ M s ] n 1 ( n 1 ) ! d s = 4 C M T n n ! .
Hence,
P { sup 0 ϖ T | z n + 1 ( ϖ ) z n ( ϖ ) | > 1 2 } 4 C 4 M T n n ! .
Since n = 0 4 C 4 M T n n ! < , by the Borel Cantelli Lemma, for almost all ω Ω , there is a n 0 = n 0 ( ω ) satisfying
sup 0 ϖ T | z n + 1 ( ϖ ) z n ( ϖ ) | 1 2 ,
for n n 0 . Therefore, if the probability is equal to 1, we have
θ + i = 0 n 1 z i + 1 ( ϖ ) z i ( ϖ ) = z n ( ϖ )
These are convergent uniformly in ϖ [ 0 , T ] .
  • Let z ( ϖ ) be the limit of z n ( ϖ ) . It is clear that z ( ϖ ) is continuous and F ϖ adapted. Moreover, using Equation (14), we can see that for every ϖ , { z n ( ϖ ) } n 1 is a Cauchy sequence in L 2 . Hence, z n ( ϖ ) z ( ϖ ) in L 2 . Letting n in Equation (12), we have
    E | z ( ϖ ) | 2 C 2 e 4 K T T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 ,
    for all 0 ϖ T .
  • Therefore, z ( ϖ ) M 2 [ 0 , T ] ; R n .
  • We can see that
    E | 0 ϖ τ s , z n ( s ) τ s , z ( s ) d s | 2 + E | 0 ϖ ϑ 1 s , z n ( s ) ϑ 1 s , z ( s ) d W ( s ) | 2 + ϰ 2 a 2 ϰ E | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 ( s , z n ( s ) ϑ 2 s , z ( s ) ) d s | 2 K ¯ T + 1 + ϰ 2 T 2 ϰ 1 a 2 ϰ 2 ϰ 1 0 T E | z n ( s ) z ( s ) | 2 d s 0 , a s n .
Hence, letting n in Equation (9), we obtain
z ( ϖ ) = θ + 0 ϖ τ q , z ( q ) d q + 0 ϖ ϑ 1 q , z ( q ) d W ( q ) + ϰ a ϰ 0 ϖ exp a 1 a ϖ q ϖ q ϰ 1 ϑ 2 q , z ( q ) d q ,
for all ϖ [ 0 , T ] , as desired. □

4. Averaging Principle

The standard form of Equation (1) is
z ϵ ( ϖ ) = θ + ϵ 0 ϖ τ s , z ϵ ( s ) d s + ϵ 0 ϖ ϑ 1 s , z ϵ ( s ) d W ( s ) + ϵ ϰ ϰ a ϰ 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ϵ ( s ) d s ,
with b , ϑ 1 , and ϑ 2 satisfying H 1 and H 2 , and ϵ ( 0 , ϵ 0 ] , with ϵ 0 ( 0 , 1 2 ) being a fixed constant. By Theorem 1, Equation (20) has a unique global solution z ϵ ( ϖ ) , ϖ [ 0 , T ] , for every ϵ ( 0 , ϵ 0 ] .
Assume that the following assumption holds true:
  • H 3 : Suppose that the measurable functions
τ ¯ ( z ) , ϑ 1 ¯ ( z ) , ϑ 2 ¯ ( z ) : R n R n
exist and verify the assumptions H 1 , H 2 . For any ( z , T 1 ) R n × [ 0 , T ] , we obtain
(1)
1 T 1 0 T 1 | τ ( s , z ) τ ¯ ( z ) | 2 d s ψ 1 ( T 1 ) ( 1 + | z | 2 ) ;
(2)
1 T 1 0 T 1 | ϑ 1 ( s , z ) ϑ 1 ¯ ( z ) | 2 d s ψ 2 ( T 1 ) ( 1 + | z | 2 ) ;
(3)
1 T 1 0 T 1 | ϑ 2 ( s , z ) ϑ 2 ¯ ( z ) | 2 d s ψ 3 ( T 1 ) ( 1 + | z | 2 ) ;
  • where ψ i ( T 1 ) are bounded positive functions such that lim T 1 ψ i ( T 1 ) = 0 for i = 1 , 2 , 3 .
  • We will show that the solution z ϵ ( ϖ ) can be approximated by the solution y ϵ ( ϖ ) of the standard equation
    y ϵ ( ϖ ) = θ + ϵ 0 ϖ τ ¯ y ϵ ( s ) d s + ϵ 0 ϖ ϑ ¯ 1 y ϵ ( s ) d W ( s ) + ϵ ϰ ϰ a ϰ 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ ¯ 2 y ϵ ( s ) d s ,
    for ϖ [ 0 , T ] .
Let us now give our main results about the relationship between z ϵ ( ϖ ) and y ϵ ( ϖ ) .
Theorem 2. 
Suppose that H 1 , H 2 , and H 3 hold. Let δ 1 > 0 be an arbitrary small constant; thus, there exist L > 0 and ϵ 1 ( 0 , ϵ 0 ] such that ϵ ( 0 , ϵ 1 ] ,
E ( sup ϖ [ 0 , L ϵ ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | 2 ) δ 1 .
Proof. 
We obtain
z ϵ ( ϖ ) y ϵ ( ϖ ) = ϵ 0 ϖ τ s , z ϵ ( s ) τ ¯ y ϵ ( s ) d s + ϵ 0 ϖ ϑ 1 s , z ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) d W ( s ) + ϵ ϰ ϰ a ϰ 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ϵ ( s ) ϑ ¯ 2 y ϵ ( s ) d s .
By the elementary inequality, we have
E sup ϖ [ 0 , u ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | 2
3 ϵ 2 E sup ϖ [ 0 , u ] | 0 ϖ τ s , z ϵ ( s ) τ ¯ y ϵ ( s ) d s | 2 + 3 ϵ E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , z ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) d W ( s ) | 2 + 3 ϰ 2 a 2 ϰ ϵ 2 ϰ E sup ϖ [ 0 , u ] | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ϵ ( s ) ϑ ¯ 2 y ϵ ( s ) | 2 = J 1 + J 2 + J 3 .
J 1 = 3 ϵ 2 E sup ϖ [ 0 , u ] | 0 ϖ τ s , z ϵ ( s ) τ ¯ y ϵ ( s ) d s | 2 6 ϵ 2 E sup ϖ [ 0 , u ] | 0 ϖ τ s , z ϵ ( s ) τ s , y ϵ ( s ) d s | 2 + 6 ϵ 2 E sup ϖ [ 0 , u ] | 0 ϖ τ s , y ϵ ( s ) τ ¯ y ϵ ( s ) d s | 2 6 ϵ 2 J 11 + 6 ϵ 2 J 12 .
By the Hölder inequality and H 1 , we derive
J 11 = E sup ϖ [ 0 , u ] | 0 ϖ τ s , z ϵ ( s ) τ s , y ϵ ( s ) d s | 2 u E 0 u | τ s , z ϵ ( s ) τ s , y ϵ ( s ) | 2 d s K ¯ u E 0 u | z ϵ ( s ) y ϵ ( s ) | 2 d s K ¯ u 0 u E sup v [ 0 , s ] | z ϵ ( v ) y ϵ ( v ) | 2 d s .
By H 3 , we have
J 12 = E sup ϖ [ 0 , u ] | 0 ϖ τ s , y ϵ ( s ) τ ¯ y ϵ ( s ) d s | 2 u E sup ϖ [ 0 , u ] 0 ϖ | τ s , y ϵ ( s ) τ ¯ y ϵ ( s ) | 2 d s u 2 E sup ϖ [ 0 , u ] 1 ϖ 0 ϖ | τ s , y ϵ ( s ) τ ¯ y ϵ ( s ) | 2 d s .
Proceeding as the proof of Theorem 1 in [34], we can obtain
J 12 u 2 sup ϖ [ 0 , u ] ψ 1 ( ϖ ) 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 .
Therefore,
J 1 6 ϵ 2 K ¯ u 0 u E sup v [ 0 , s ] | z ϵ ( v ) y ϵ ( v ) | 2 d s + 6 ϵ 2 u 2 sup ϖ [ 0 , u ] ψ 1 ( ϖ ) 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 .
J 2 = 3 ϵ E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , z ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) d W ( s ) | 2 = 3 ϵ E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , z ϵ ( s ) ϑ 1 s , y ϵ ( s ) + ϑ 1 s , y ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) d W ( s ) | 2 6 ϵ E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , z ϵ ( s ) ϑ 1 s , y ϵ ( s ) d W ( s ) | 2 + 6 ϵ E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , y ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) d W ( s ) | 2 6 ϵ J 21 + 6 ϵ J 22 .
According to Theorem 7.2 (p. 40 in [35]) and H 1 , we have
J 21 = E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , z ϵ ( s ) ϑ 1 s , y ϵ ( s ) d W ( s ) | 2 4 E 0 u | ϑ 1 s , z ϵ ( s ) ϑ 1 s , y ϵ ( s ) | 2 d s 4 K ¯ E 0 u | z ϵ ( s ) y ϵ ( s ) | 2 d s 4 K ¯ 0 u E sup v [ 0 , s ] | z ϵ ( v ) y ϵ ( v ) | 2 d s .
By H 3 , we derive
J 22 = E sup ϖ [ 0 , u ] | 0 ϖ ϑ 1 s , y ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) d W ( s ) | 2 4 E 0 u | ϑ 1 s , y ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) | 2 d s 4 u E 1 u 0 u | ϑ 1 s , y ϵ ( s ) ϑ ¯ 1 y ϵ ( s ) | 2 d s 4 u sup ϖ [ 0 , u ] ψ 2 ( ϖ ) 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 .
Hence,
J 2 24 ϵ K ¯ 0 u E sup v [ 0 , s ] | z ϵ ( v ) y ϵ ( v ) | 2 d s + 24 ϵ u sup ϖ [ 0 , u ] ψ 2 ( ϖ ) 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 .
J 3 = 3 ϰ 2 a 2 ϰ ϵ 2 ϰ E sup ϖ [ 0 , u ] | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ϵ ( s ) ϑ ¯ 2 y ϵ ( s ) | 2 6 ϰ 2 a 2 ϰ ϵ 2 ϰ E sup ϖ [ 0 , u ] | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ϵ ( s ) ϑ 2 s , y ϵ ( s ) d s | 2 + 6 ϰ 2 a 2 ϰ ϵ 2 ϰ E sup ϖ [ 0 , u ] | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , y ϵ ( s ) ϑ ¯ 2 y ϵ ( s ) d s | 2 6 ϰ 2 a 2 ϰ ϵ 2 ϰ J 31 + 6 ϰ 2 a 2 ϰ ϵ 2 ϰ J 32 .
By the Hölder inequality and H 1 , we have
J 31 = E sup ϖ [ 0 , u ] | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , z ϵ ( s ) ϑ 2 s , y ϵ ( s ) d s | 2 sup ϖ [ 0 , u ] 0 ϖ exp 2 a 1 a ϖ s ϖ s 2 ϰ 2 d s E 0 u | ϑ 2 s , z ϵ ( s ) ϑ 2 s , y ϵ ( s ) | 2 d s sup ϖ [ 0 , u ] 0 ϖ ϖ s 2 ϰ 2 d s E 0 u | ϑ 2 s , z ϵ ( s ) ϑ 2 s , y ϵ ( s ) | 2 d s u 2 ϰ 1 2 ϰ 1 K ¯ E 0 u | z ϵ ( s ) y ϵ ( s ) | 2 d s u 2 ϰ 1 2 ϰ 1 K ¯ 0 u E sup υ [ 0 , s ] | z ϵ ( v ) y ϵ ( v ) | 2 d s .
By the Hölder inequality and H 3 , we obtain
J 32 = E sup ϖ [ 0 , u ] | 0 ϖ exp a 1 a ϖ s ϖ s ϰ 1 ϑ 2 s , y ϵ ( s ) ϑ ¯ 2 y ϵ ( s ) d s | 2 u 2 ϰ 2 ϰ 1 E 1 u 0 u | ϑ 2 s , y ϵ ( s ) ϑ ¯ 2 y ϵ ( s ) | 2 d s u 2 ϰ 2 ϰ 1 ψ 3 ( u ) ( 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 ) .
Consequently,
J 3 6 ϰ 2 ϵ 2 ϰ a 2 ϰ ( 2 ϰ 1 ) u 2 ϰ 1 K ¯ 0 u E ( sup v [ 0 , s ] | z ϵ ( v ) y ϵ ( v ) | 2 ) d s + 6 ϰ 2 ϵ 2 ϰ a 2 ϰ ( 2 ϰ 1 ) u 2 ϰ ( ψ 3 ( u ) ) ( 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 ) .
Substituting Equations (28)–(36) into Equation (23) and using Lemma 1, we can derive that
E sup ϖ [ 0 , u ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | 2 6 ϵ K ¯ ( ϵ u + 4 + ϰ 2 ϵ 2 ϰ 1 a 2 ϰ ( 2 ϰ 1 ) u 2 ϰ 1 ) 0 u E ( sup υ [ 0 , s ] | z ϵ ( υ ) y ϵ ( υ ) | 2 ) d s + 6 ϵ u ( ϵ u ( sup l [ 0 , u ] ψ 1 ( l ) ) + 4 ( sup l [ 0 , u ] ψ 2 ( l ) ) + ϰ 2 ϵ 2 ϰ 1 a 2 ϰ ( 2 ϰ 1 ) u 2 ϰ 1 ψ 3 ( u ) ) × ( 1 + E sup ϖ [ 0 , u ] | y ϵ ( ϖ ) | 2 ) ϵ L 3 + ϵ L 2 0 u E ( sup υ [ 0 , s ] | z ϵ ( υ ) y ϵ ( υ ) | 2 ) d s ,
where
L 2 = 6 K ¯ ( ϵ T + 4 + ϰ 2 ϵ 2 ϰ 1 a 2 ϰ ( 2 ϰ 1 ) T 2 ϰ 1 ) ,
and
L 3 = 6 T ( ϵ T sup l [ 0 , T ] ψ 1 ( l ) + 4 sup l [ 0 , T ] ψ 2 ( l ) + ϰ 2 ϵ 2 ϰ 1 a 2 ϰ ( 2 ϰ 1 ) T 2 ϰ 1 sup l [ 0 , T ] ψ 3 ( l ) ) ( 1 + L 1 ) .
Using the Gronwall inequality, we derive
E ( sup ϖ [ 0 , u ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | 2 ) ϵ L 3 e ϵ L 2 u .
Therefore, given any number δ 1 > 0 , there exists L > 0 and ϵ 1 ( 0 , ϵ 0 ] satisfies for every ϵ ( 0 , ϵ 1 ] ,
E ( sup ϖ [ 0 , L ϵ ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | 2 ) δ 1 .
Next, Theorem 2 shows the convergence, in probability, between the states z ϵ ( ϖ ) , y ϵ ( ϖ ) .
Theorem 3. 
Suppose that the PIDSFOS Equations (20) and (21) both satisfy H 1 - H 3 . Let δ 1 > 0 be an arbitrary small constant; thus, there exist L > 0 and ϵ 1 ( 0 , ϵ 0 ] such that ϵ ( 0 , ϵ 1 ] ,
lim ϵ 0 P ( sup ϖ [ 0 , L ϵ ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | > δ 1 ) = 0 .
Proof. 
Given any constant δ 1 > 0 , using Theorem 2 and Chebyshev’s inequality, we can derive that
P ( sup ϖ [ 0 , L ϵ ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | > δ 1 ) 1 δ 1 2 E ( sup ϖ [ 0 , L ϵ ] | z ϵ ( ϖ ) y ϵ ( ϖ ) | 2 ) 1 δ 1 2 ϵ L 3 e ϵ L 2 T .
Setting ϵ 0 , Equation (39) holds. □
Remark 1. 
For a = 1 , we obtain the results given in [25].

5. Illustrative Example

In the following, we will exhibit an example to prove the interest of our results.
Example 1. 
Consider Equation (20), for any ϵ ( 0 , 1 4 ] and ϖ [ 0 , T ] , where
z ϵ ( ϖ ) M 2 [ 0 , T ] ; R τ ( ϖ , z ϵ ( ϖ ) ) = ϖ + 2 ϖ + 3 sin ( z ϵ ( ϖ ) ) . ϑ 1 ( ϖ , z ( ϖ ) ) = 1 + e ϖ arctan ( z ϵ ( ϖ ) ) ϑ 2 ( ϖ , z ( ϖ ) ) = 1 + e ϖ 1 + e ϖ cos ( z ϵ ( ϖ ) )
Set ( η , θ 1 , θ 2 ) [ 0 , T ] × R × R ; thus
| τ ( η , θ 1 ) τ ( η , θ 2 ) | 2 | ϑ 1 ( η , θ 1 ) ϑ 1 ( η , θ 2 ) | 2 | ϑ 2 ( η , θ 1 ) ϑ 2 ( η , θ 2 ) | 2 K ¯ | θ 1 θ 2 | 2 ,
| τ ( η , θ ) | 2 | ϑ 1 ( η , θ ) | 2 | ϑ 2 ( η , θ ) | 2 K ( 1 + | θ | 2 ) .
Let τ ¯ ( z ) = sin ( z ) , ϑ 1 ¯ ( z ) = arctan ( z ) , and ϑ 2 ¯ ( z ) = cos ( z ) . Thus, for any T 1 [ 0 , T ] , we obtain
1 T 1 0 T 1 | τ ( s , z ) τ ¯ ( z ) | 2 d s sin 2 ( z ) 1 T 1 0 T 1 1 ( s + 3 ) 2 d s 1 T 1 + 3 z 2 ψ 1 ( T 1 ) 1 + | z | 2 ,
1 T 1 0 T 1 | ϑ 1 ( s , z ) ϑ 1 ¯ ( z ) | 2 d s 1 T 1 arctan 2 ( z ) 0 T 1 e 2 s d s e 2 e 2 T 1 2 T 1 z 2 ψ 2 ( T 1 ) 1 + | z | 2 ,
and
1 T 1 0 T 1 | ϑ 2 ( s , z ) ϑ 2 ¯ ( z ) | 2 d s 1 T 1 cos 2 ( z ) 0 T 1 e s 1 + e s d s ln ( 2 ) ln ( 1 + e T 1 ) cos 2 ( z ) T 1 ψ 3 ( T 1 ) 1 + | z | 2 ,
where ψ 1 ( T 1 ) = 1 T 1 + 3 , ψ 2 ( T 1 ) = e 2 e 2 T 1 2 T 1 and ψ 3 ( T 1 ) = 1 T 1 ln ( 2 ) ln ( 1 + e T 1 ) .
  • Consequently, H 1 - H 3 hold with K = K ¯ = 4 . Finally, Theorem 2 is satisfied.

6. Conclusions

In this article, we have investigated the existence and uniqueness of PIDSFOS of order ϖ ( 1 2 , 1 ) using the Picard iteration technique and the fractional proportional integral properties. We have proved the convergence of the solution of the averaged PIDSFOS to the solution of the standard PIDSFOS in the sense of the mean square and also in probability by the moment and the Gronwall inequalities. Finally, we have presented an example to illustrate our results. In future work, we can extend this paper to a time-delay system with a non-Lipschitz condition.

Author Contributions

Validation, H.M.S.R.; Formal analysis, L.M. and H.A.O.; Investigation, A.B.M.; Resources, A.B.M.; Writing—original draft, L.M.; Writing—review & editing, S.B. All authors have read and agreed to the published version of the manuscript.

Funding

The Deputyship for Research & Innovation, Ministry of Education in Saudi Arabia, project number: IFP22UQU4330052DSR040.

Data Availability Statement

Not applicable.

Acknowledgments

The authors extend their appreciation to the Deputyship for Research & Innovation, Ministry of Education in Saudi Arabia for funding this research work through the project number IFP22UQU4330052DSR040.

Conflicts of Interest

The authors declare no conflict of interest.

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Ben Makhlouf, A.; Mchiri, L.; Othman, H.A.; Rguigui, H.M.S.; Boulaaras, S. Proportional Itô–Doob Stochastic Fractional Order Systems. Mathematics 2023, 11, 2049. https://doi.org/10.3390/math11092049

AMA Style

Ben Makhlouf A, Mchiri L, Othman HA, Rguigui HMS, Boulaaras S. Proportional Itô–Doob Stochastic Fractional Order Systems. Mathematics. 2023; 11(9):2049. https://doi.org/10.3390/math11092049

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Ben Makhlouf, Abdellatif, Lassaad Mchiri, Hakeem A. Othman, Hafedh M. S. Rguigui, and Salah Boulaaras. 2023. "Proportional Itô–Doob Stochastic Fractional Order Systems" Mathematics 11, no. 9: 2049. https://doi.org/10.3390/math11092049

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